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The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. 输入描述: Each input file contains one test case. For each case, the first line contains an integer N (in [3, 105]), followed by N integer distances D1 D2 ... DN, where Di is the distance between the i-th and the (i+1)-st exits, and DN is between the N-th and the 1st exits. All the numbers in a line are separated by a space. The second line gives a positive integer M (<=104), with M lines follow, each contains a pair of exit numbers, provided that the exits are numbered from 1 to N. It is guaranteed that the total round trip distance is no more than 107. 输出描述: For each test case, print your results in M lines, each contains the shortest distance between the corresponding given pair of exits. 输入例子: 5 1 2 4 14 9 3 1 3 2 5 4 1 输出例子: 3 10 7

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#include #include #include #include #include using namespace std; int v[100001],dis[100001]; int main() { int n,m,sum=0; scanf("%d",&n); dis[0]=0; for(int i=0;iright) swap(left,right); //for(int i=left-1;i
 
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