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一个学生的信息是:姓名,学号,性别,年龄等信息,用一个链表,把这些学生信息连在一起, 给出一个age, 在些链表中删除学生年龄等于age的学生信息。

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1 个答案

#include "stdio.h"

#include

"conio.h"

 

struct stu{

char name[20];

char sex;

int no;

int age;

struct stu * next;

}*linklist;

struct stu

*creatlist(int n)

{

int i;

//h为头结点,p为前一结点,s为当前结点

struct stu *h,*p,*s;

h = (struct stu*)malloc(sizeof(struct stu));

h->next = NULL;

p=h;

for(i=0;i

{

s = (struct stu*)malloc(sizeof(struct stu));

p->next = s;

printf("Please input the information of the student: name sex no age \n");

scanf("%s %c %d %d",s->name,&s->sex,&s->no,&s->age);

s->next = NULL;

p = s;

}

printf("Create successful!");

return(h);

}

void deletelist(struct stu *s,int a)

{

struct stu *p;

while(s->age!=a)

{

p = s;

s = s->next;

}

if(s==NULL)

printf("The record is not exist.");

else

{

p->next = s->next;

printf("Delete successful!");

}

}

void display(struct stu *s)

{

s = s->next;

while(s!=NULL)

{

printf("%s %c %d %d\n",s->name,s->sex,s->no,s->age);

s = s->next;

}

}

int main()

{

struct stu *s;

int n,age;

printf("Please input the length of seqlist:\n");

scanf("%d",&n);

s = creatlist(n);

display(s);

printf("Please input the age:\n");

scanf("%d",&age);

deletelist(s,age);

display(s);

return 0;

}

 
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